(b+3)(b^2-5b-7)=0

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Solution for (b+3)(b^2-5b-7)=0 equation: 


Simplifying
(b + 3)(b2 + -5b + -7) = 0

Reorder the terms:
(3 + b)(b2 + -5b + -7) = 0

Reorder the terms:
(3 + b)(-7 + -5b + b2) = 0

Multiply (3 + b) * (-7 + -5b + b2)
(3(-7 + -5b + b2) + b(-7 + -5b + b2)) = 0
((-7 * 3 + -5b * 3 + b2 * 3) + b(-7 + -5b + b2)) = 0
((-21 + -15b + 3b2) + b(-7 + -5b + b2)) = 0
(-21 + -15b + 3b2 + (-7 * b + -5b * b + b2 * b)) = 0
(-21 + -15b + 3b2 + (-7b + -5b2 + b3)) = 0

Reorder the terms:
(-21 + -15b + -7b + 3b2 + -5b2 + b3) = 0

Combine like terms: -15b + -7b = -22b
(-21 + -22b + 3b2 + -5b2 + b3) = 0

Combine like terms: 3b2 + -5b2 = -2b2
(-21 + -22b + -2b2 + b3) = 0

Solving
-21 + -22b + -2b2 + b3 = 0

Solving for variable 'b'.

The solution to this equation could not be determined.

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